18y^2=258

Solution for 18y^2=258 equation:

18y^2=258

We move all terms to the left:

18y^2-(258)=0

a = 18; b = 0; c = -258;
Δ = b2-4ac
Δ = 02-4·18·(-258)
Δ = 18576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18576}=\sqrt{144*129}=\sqrt{144}*\sqrt{129}=12\sqrt{129}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{129}}{2*18}=\frac{0-12\sqrt{129}}{36}
=-\frac{12\sqrt{129}}{36}
=-\frac{\sqrt{129}}{3}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{129}}{2*18}=\frac{0+12\sqrt{129}}{36}
=\frac{12\sqrt{129}}{36}
=\frac{\sqrt{129}}{3}
$